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blondinia [14]
3 years ago
6

Is the simplified form of 2 v3 · 2 v6 rational?

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

No

Step-by-step explanation:

2√3 × 2√6

= 4√18

= 4√9*2

= 4( 2√2)

= 8√2

Just multiply the numbers under the radical together.  √3 × √6 = √18.  √18 can be written as √9*2, or 3√3.

√2 is irrational, so the answer will be irrational

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(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col
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Answer:

a) n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=16 represent the population standard deviation

n represent the sample size  

Solution to the problem

Part a

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

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Answer:

Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

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2 years ago
If cos θ > 0, which quadrant(s) could the terminal side of θ lie?
Sergeeva-Olga [200]

Answer:

I and IV

Step-by-step explanation:

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Can remember by All Star Trig Class

meaning all the trig funtions are positive in quadrant I

sin is positive in II

tan is positive in III

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8 0
3 years ago
Ms.Groves has trays of paint for students in her art class.each tray has 5 colors.one of the colors is purple.what fraction of t
seropon [69]
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2 years ago
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