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sattari [20]
3 years ago
8

Suppose two fractions are both less than 1. Can their sum be greater than 1? Greater than 2?

Mathematics
1 answer:
lesantik [10]3 years ago
4 0
Yes they can be greater than one no they can't be grater than 2
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A certain bacteria is growing at a rate of 4 percent each day. If the culture of bacteria has 5,000 bacteria today, how many bac
Virty [35]
This is the concept of exponential growth, To get the number of bacteria after 10 days we use the formula:
f(t)=ae^(kt)
where;
a=initial number=5000
k=constant of proportionality= 0.04
t=time=10 days
f(t)=future number
thus the number of bacteria in 10 days will be:
f(t)=5000e^(0.04*10)
f(t)=7,459.12
The answer is 7,459.12
8 0
2 years ago
For Joe's illness, the doctor gave him a prescription of 28 pills. He needs to take 4 pills the first day, and then 2 pills each
kiruha [24]

Answer:

12 days.

Step-by-step explanation:

I looked at it this way:

He has to take 4/28 pills the first day, so it's 28-4=24. Then I divided 24 by 2.

In simpler terms:

28-4=24

24/2

12

8 0
3 years ago
What is 4 1/2 divided by 7 1/3 and multiplied by 1 3/5?
Luba_88 [7]
I did the work and it says 0.3683492496 and more number but i believe its 0.3 without all those other numbers

6 0
3 years ago
It took Fred 17 days to save $36.55. At that rate, how long would it take him to save $70.95?
Vlad1618 [11]

Answer:

Fred would take 33 days to save $ 70.95.

Step-by-step explanation:

The number of days (t) is directly proportional to the quantity of money saved (c), in monetary units, then we can calculate the time taken to save $ 70.95 by simple rule of three:

t = 17\,d\,\times \frac{\$\,70.95}{\$\,36.55}

t = 33\,d

Fred would take 33 days to save $ 70.95.

4 0
2 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Ipatiy [6.2K]

Answer:

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

Step-by-step explanation:

2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c =  - 3 \\\\x = \frac{-b^2\  \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

3 0
2 years ago
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