rgb_scale = 255
cmyk_scale = 100
def rgb_to_cmyk(r,g,b):
if (r == 0) and (g == 0) and (b == 0):
return 0, 0, 0, cmyk_scale
# rgb [0,255] -> cmy [0,1]
c = 1 - r / float(rgb_scale)
m = 1 - g / float(rgb_scale)
y = 1 - b / float(rgb_scale)
min_cmy = min(c, m, y)
c = (c - min_cmy)
m = (m - min_cmy)
y = (y - min_cmy)
k = min_cmy
return c*cmyk_scale, m*cmyk_scale, y*cmyk_scale, k*cmyk_scale
def cmyk_to_rgb(c,m,y,k):
r = rgb_scale*(1.0-(c+k)/float(cmyk_scale))
g = rgb_scale*(1.0-(m+k)/float(cmyk_scale))
b = rgb_scale*(1.0-(y+k)/float(cmyk_scale))
return r,g,b
Answer:
Vigenère
Explanation:
It is a method of encrypting alphabetic text by using a form of polyalphabetic substitution. A polyalphabetic cipher is any cipher based on substitution, ie using multiple substitution of alphabets. The encryption is done using a Vigenère table.
To encrypt a message using the Vigenère Cipher you choose a keyphrase. Then repeat this keyword over and over until it is the same length as the original text; this is referred to as a keystream.
Answer:
Explanation:
A stack item behaves like Last In First Out, which is equivalent to First In Last Out. FIFO and LILO are also equivalent, but they describe a queue.
Answer:
Refer below.
Explanation:
Because we are inserting commands to beq, we will need an execution of the ALU, and then a register write. This result in and increase cycle time of the PC relative branch:
440+90=530ps.
As it is the longest time to execute, so its a critical path
Answer: A polaroid
Explanation: I have all these cameras
