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velikii [3]
3 years ago
10

Can someone help me?

Mathematics
1 answer:
Vilka [71]3 years ago
5 0

When finding an integer you figure out if the integer is positive or negative; positive as in being above a certain point, such as sea level, and negative as in being below that certain point. Being positive might also mean going up or moving forward; and vice versa for being negative.

1. 282 feet below, so it is <u>-282</u>

2. 3 inches more, so it is <u>3</u>

3. gained 5 points and lost 4 points, so <u>5</u> & <u>-4</u>

4. The airplane pilot could have gone down in altitude by 100 meters, or could have gone up in altitude by 100 meters.

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\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ -3}}\quad ,&{{ 2}})\quad &#10;%  (c,d)&#10;&({{ m}}\quad ,&{{ 2}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf \textit{we know the distance from m,2 and -3,2(center) is the radius}&#10;\\\\\\&#10;d=8\implies 8=\sqrt{[m-(-3)]^2+[2-2]^2}&#10;\\\\\\&#10;8=\sqrt{(m+3)^2+(0)^2}\implies 8=\sqrt{(m+3)^2}\implies 8^2=(m+3)^2&#10;\\\\\\&#10;64=(m+3)^2\implies \sqrt{64}=\sqrt{(m+3)^2}\implies 8=m+3&#10;\\\\\\&#10;8-3=m
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