Disagree
They say there are three pairs of integers that match, well..
1+7=8
2+6=8
3+5=8
-1+-7=-8
-2+-6=-8
-3+-5=-8
The same applies to negative integers because the absolute value of -3 and 3 is still 3. No matter the negative or not. So that gives us 6 pairs not 3.
It would be c I think: the problem says 2 divided by five and all the others are 5 divided by two
X - intercepts y = 0, then
<span>4(0+3)=−2(x+6)
12 = -2x -12
2x = -24
x=-24/2
x = -12
</span>y- intercepts x = 0 then
4(y+3)=−2(0+6)
4y +12 = -12
4y = -24
y = -24/4
y = -6
a^2 +b^2 = (2.5sqrt(2))^2
2a^2 = 6.25 *2
a^2 = 6.25
a = sqrt(6.25)
a = 2.5
length of each side = 2.5 units
