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Anon25 [30]
3 years ago
15

What is the solution for x in the equation?

Mathematics
1 answer:
navik [9.2K]3 years ago
3 0

Step-by-step explanation:

option C

hope it helps

thank you

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Find the x-intercept and y-intercept of the line.<br> 3x + y = 6
Dafna1 [17]

Answer:

x = (6 - y)÷ 3

Step-by-step explanation:

3x + y = 6

3x = 6 - y

x = 6 - y ÷ 3

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ABCD is a isosceles trapezoid with AB=10, DB=8 and angle A=120 degrees what is the length of CD
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Answer:

The answer is 10.6 (I'm sorry if it's wrong)

Step-by-step explanation:

found out what D and B is (they both are 4 I think) then add 10 with 8 then divide 120 with 18 which is 6.6 then add what D is and then I got 10.6

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3 years ago
What is the angle of elevation to the nearest tenth of a degree to the top of a 35-ft building from 75 ft away?
choli [55]
You set up the equation with 35/75 and you said that equal to X tan. You then take your calculator and type in 35÷75 and press the equal button. You then hit the second function button and then press tan and it will give you 25

6 0
4 years ago
What are the possible values of x in x2 + 3x + 3 = 0?
e-lub [12.9K]

To solve a quadratic equation like ax^2+bx+c=0, you can use the quadratic formula

x_{1,2} = \cfrac{-b\pm\sqrt{b^2-4ac}}{2a}

In your case, a = 1, b = c = 3, so the formula becomes

x_{1,2} = \cfrac{-3\pm\sqrt{(-3)^2-4\cdot 1\cdot 3}}{2\cdot 1}

We can simplify the expression:

x_{1,2} = \cfrac{-3\pm\sqrt{9-12}}{2} = \cfrac{-3\pm\sqrt{-3}}{2}

Since -3 is negative, its square root is computed as

\sqrt{-3} = \sqrt{-1\cdot 3} = \sqrt{-1}\sqrt{3} = \sqrt{3}i

So, the solutions are

x = \cfrac{-3+i\sqrt{3}}{2} \text{ or } x = \cfrac{-3-i\sqrt{3}}{2}

4 0
4 years ago
Read 2 more answers
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