Answer:
John is 9.21 km form the school.
Step-by-step explanation:
John leaves school to go home. His bus drives 6 kilometres north and then goes 7 kilometres west. It is required to find John's distance from the school. It is equal to the shortest path covered or its displacement. So,
![d=\sqrt{6^2+7^2} \\\\d=9.21\ km](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B6%5E2%2B7%5E2%7D%20%5C%5C%5C%5Cd%3D9.21%5C%20km)
So, John is 9.21 km form the school.
560 ft^2
20ft x 10ft = 200 ft^2
+
12ft x 30ft = 360 ft^2
=
560 ft^2
First this is a positive slope go left to right, next the score is around 50 to 60 percent, the slope is 8
Answer:
7 + 5a
Step-by-step explanation:
3-(- 2a -4)+3a = 3+2a +4 +3a = 7 + 5a
Into the equation y=−3x+b substitute 5 for x and 2 for y, obtaining:
2 = -3(5) + b. Then 2 = -15 + b, or b = 17.