All categories

3 years ago

How do i rewriting 2 5/10

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

6 0

2.5 if youre rewriting in decimal form

You might be interested in

What is the <br> Midpoint of -3,8 -7,-6

Leni [432]

Answer:

(-5,1)

Step-by-step explanation:

5 0

3 years ago

If two triangles are congruent, which of the following statements must be true? Check all that apply.

melomori [17]

When figures are congruent, they have the same shape and size. All measures of one of the figures are identical to the corresponding measures of the other.

Of these statements, the following must be true ...

B. The corresponding sides of the triangles are congruent
C. The corresponding angles of the triangles are congruent
D. The triangles have the same shape and size

5 0

3 years ago

Read 2 more answers

Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?

sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have $V=IR^{2}$ and let $H$ be the subset of $V$ of all points on the line

$4x+3y=12$

We need to find if $H$ is a subspace of the vector space $V$ .

In $IR^{2}$ all the possibilities for own subspace of the vector space $IR^{2}$ are :

$IR^{2}$ itself.

The vector $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$

All lines in $IR^{2}$ that passes through the origin ( $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$ )

We know that $H$ is the subset of $IR^{2}$ of all points on the line $4x+3y=12$

If we look at the equation, the point $\left[\begin{array}{c}0&0\end{array}\right]$ doesn't verify it because :

$4x+3y=12\\4(0)+3(0)=12\\0=12$

Which is an absurd. Therefore, $H$ doesn't contain the origin (and $H$ is a line in $IR^{2}$ ). Finally, it can't be a vector space of $V=IR^{2}$

8 0

3 years ago

The given line passes through the points (-4,-3) and (4,

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

first we gotta find the slope of the first line

(-4,-3),(4,1)

slope = (y2 - y1) / (x2 - x1) = (1- (-3) / (4 - (-4) = (1 + 3) / (4 + 4) = 4/8 = 1/2

so the slope is 1/2.....so we are looking for a line that is perpendicular....perpendicular lines have negative reciprocal slopes...all that means is flip the slope and change the sign....so the slope we need is :

1/2....flip it....2/1.....change the sign....-2.....we need a -2 slope

y - y1 = m(x - x1)

slope = -2

(-4,3)...x1 = -4 and y1 = 3

now sub

y - 3 = -2(x - (-4) =

y - 3 = -2(x + 4) <=====

6 0

3 years ago

the graph of a liner relationship has a slope of -5 and passes through the point (2, -12). write tge equation of the liner in th

bixtya [17]

Answer:

y = -5x - 2

Step-by-step explanation:

equation formula: y = mx + c

m = -5

-12 = -5(2) + c

c = -2

⇒ y = -5x - 2

5 0

2 years ago