F(x)=5x^2 Has minimum (0,0)
g(x) = f(x) + 2 Shifts the graph two units up, then the minimum is 2+0=2.
h(x) = g(x+4) Shifts the graph four units left, then the minimum is at 0-4 = -4.
Then h(x) = 5(x+4)^2 + 2 has the minimum (-4,2)
And p(x) = -5(x+4)^2 + 2 has the maximum (-4,2)
What’s da problem that u have?
Im assuming the problem is x^2-16, which would be factored to (x-4)(x+4)
The answer should be 9 rounded because 2 pi r 56.5 will give u that.
D bc it needs to have a y intercept of -1
