Question

Please help me with this question!! Find angle x and y.

Answer 1

Answer:

x= 100º

y= 260º

Step-by-step explanation:

x= 180º-42º-38º

x= 100º

y= 360º-100º

y=260º

(I'm not sure if it's right, but I hope I helped :) )

Answer 2

Answer:

x =80°

y = 280°

Step-by-step explanation:

Given: $AB \parallel CD$

Extend segment CE in the direction of E in such a way that it intersects ray AB at point say P.

$\therefore m\angle APE = m\angle ECD..(Alternate\: \angle s)\\\because m\angle ECD = 42°\\\therefore m\angle APE = 42°$

So, x° would be the exterior angle of $\triangle AEP.$

Hence, by remote interior angle theorem of a triangle, we have:

$x = 38° + 42°\\\huge\purple{\boxed{x = 80° }}\\\\y = 360\degree - 80\degree\\\huge\red{\boxed{y= 280\degree}}$