Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
First number: x = 19
Second number: Y = -5
x + 2y = 9
2x + y = 33
Step-by-step explanation:
am-an+bm-bn
m(a+b)-n(a+b)
(m-n)(a-b)
Answer:
the answer is $8.75
Step-by-step explanation:
