Solve the problem and then click on the correct graph. y < |x + 3|

Mathematics

2 answers:

trapecia [35]3 years ago

6 0

The second picture should be the correct graph or the one which has its blue on the bottom side.

Marianna [84]3 years ago

3 0

The 2nd graph is your answer!

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As a member of a consumer group, you are interested in determining if the average number of crisps per can of Pringles is less t

Elza [17]

Answer:

Option A. The average number of crisps per can of Pringles is less than 100.

Step-by-step explanation:

We are given that the member of consumer group is wants to determine whether the average number of crisps per can of pringles is less than the average number of crisp mentioned in an advertisement whereas average number of crisp mentioned in an advertisement are 100 crisps per can. We know that the null hypothesis always contains equality and alternative hypothesis is contrary to the null hypothesis. Thus, the alternative hypothesis would be that the average number of crisps are less than 100 per can. So, the formed hypothesis are

Null hypothesis: The average number of crisps per can of Pringles is 100.

Alternative hypothesis: The average number of crisps per can of Pringles is less than 100.

6 0

3 years ago

In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the

oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation(which is the square root of the variance) $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

$\mu = 503, \sigma = \sqrt{9604} = 98$