Do you have Any answer choices
Answer:
Both Recessive
Explanation:
Because, when you say that they're both the same then that just gives clarity of them both being Recessive traits. So honestly, in my opinion, Both dominant alleles & both Recessive alleles are both the the same.
Answer:Cellular Respiration
Explanation:
Cellular respiration is the process by which cells produce energy, and is broken down into three more steps: glycolysis, Kreb’s cycle, and electron transport chain. Glycolysis requires glucose, two ATP, and NAD+, and two ADP, and produces two pyruvate, four ATPs, two NADH, and two H2O. The Kreb’s Chcle and thus the downstream electron transport chain require acetyl-CoA, one ADP, three NAD+, and one FAD, but pyruvate oxidation needs to happen prior to the Kreb’s Cycle, thus this is where the Oxygen is used and produced into two CO2.
Answer:
D) B/b;S/s (x) b/b;s/s
Explanation:
Parent 1 : belted syndactylous sow
Since it is showing dominant phenotype for both the traits, it can either be BBSS or BbSs
Parent 2: unbelted cloven-hoofed
Since it is showing recessive phenotype for both the traits, it can only have bbss genotype
If we assume parent 1 to be BBSS all the resulting progeny with bbss will have dominant phenotype which is not the case.
If we assume parent 1 to be BbSs:
BbSs X bbss =
BbSs : belted syndactylous
bbSs : unbelted syndactylous
Bbss : belted cloven
bbss : unbelted cloven
The progeny will be produced in 1:1:1:1 ratio which means that each of them will make 25% of the population.
Hence, parent 1 will have BbSs genotype and parent 2 will have bbss genotype
For full activation of a cyclin-CDK complex, an enzyme called CDK-activating kinase must phosphorylate an amino acid near the CDK active site.
CDK-activating kinase (CAK) actuates the cyclin-CDK complex by phosphorylation of an amino acid i.e. threonine residue 160 near the CDK active site.
CAK is a member of the CDK family and serves as a positive regulator of CDK1, CDK2, CDK4, as well as CDK6.
CDK activation needs two steps. Primarily, the cyclin should attach to the CDK and secondly, CAK should phosphorylate the cyclin-CDK complex on the threonine residue 160, that is situated in the CDK activation section.
To learn more about cyclin here
brainly.com/question/13327301
#SPJ4
