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Zarrin [17]
3 years ago
12

uring a period of extreme cold, the average daily temperature dropped decreased by 112°Feach day. How many days did it take for

the temperature to decrease by 9°F? Which equation would you use to find the solution?
Mathematics
1 answer:
marissa [1.9K]3 years ago
7 0

Answer:

lol

Step-by-step explanation:

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2cosx=2sin2x. Sin2x is an identity for 2sinxcos. So 2[2sinxcosx] gives you 4sinxcosx. 2cosx=4sinxcosx. Divide 2cosx on both sides and gives you 2sinx=0 and divide again, sinx=0. Sinx is 0 at 0 and 360 degrees, or pi and 2pi. So thats what x would be. 0,360,pi,2pi.
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3 years ago
A stand is a frustum shape, formed by removing a small square-based pyramid from the top of
kupik [55]

The frustum can be considered as consisting of a square pyramid, less the

cut volume.

  • The mass of the stand, is approximately 18.60905 kg

Reasons:

The given parameter of the frustum are;

The density of the frustum, ρ = 85 g/cm³

Height of pyramid, h = 9 cm

Side length of base = 10 cm

Height of frustum

By proportional shapes, the side length of the top of the frustum can be found as follows;

\dfrac{4 \, cm}{9 \, cm} = \dfrac{x}{10 \, cm}

x = \dfrac{4 \, cm}{9 \, cm} \times 10 \, cm = 4\frac{4}{9} \, cm

V = \dfrac{h}{3} \times \left(B_1 + B_2 + \sqrt{B_1 \times B_2} \right)

B₁ = 10², B₂ = \left(4\frac{4}{9} \right)^2

Therefore;

V = \dfrac{4}{3} \times \left(10^2 + \left(4\frac{4}{9}  \right)^2  + \sqrt{10^2 \times  \left(4\frac{4}{9}  \right)^2} \right) \approx 218.93

The volume of the stand, V ≈ 218.93 cm³

Mass = Volume × Density

∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.

Learn more here:

brainly.com/question/24323975

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100 points, if i dont pass this i fail my class.
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Answer:

B.

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I got it correct on edginuity

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