Answer:
P(A) = 86/100
P(B) = 79/100
P(A') = 14/100
P(A U B) = 95/100
P(A' U B) = 84/100
Step-by-step explanation:
i. P(A) = number of disks with high shock resistance/total number of disks
= (70+16)/100
= 86/100
ii. P(B) = number of disks with high scratch resistance/total number of disks
= (70+9)/100
= 79/100
iii. P(A') = number of disks without high shock resistance/total number of disks
= (100-86)/100
= 14/100
iv. P(AUB) = number of disks with high shock resistance or high scratch resistance/total number of disks
= (70+9+16)/100
= 95/100
v. P(A'UB) = number of disks without high shock resistance or with high scratch resistance/total number of disks
= (5+9+70)/100
= 84/100
Answer:
It would be $42.96.
Step-by-step explanation:
Reduce a 24 cm by 36 cm photo to 3/4 original size.
The most logical way to do this is to keep the width-to-height ratio the same: It is 24/36, or 2/3. The original photo has an area of (24 cm)(36 cm) = 864 cm^2.
Let's reduce that to 3/4 size: Mult. 864 cm^2 by (3/4). Result: 648 cm^2.
We need to find new L and new W such that W/L = 2/3 and WL = 648 cm^2.
From the first equation we get W = 2L/3. Thus, WL = 648 cm^2 = (2L/3)(L).
Solve this last equation for L^2, and then for L:
2L^2/3 = 648, or (2/3)L^2 = 648. Thus, L^2 = (3/2)(648 cm^2) = 972 cm^2.
Taking the sqrt of both sides, L = + 31.18 cm. Then W must be 2/3 of that, or W = 20.78 cm.
Check: is LW = (3/4) of the original 864 cm^2? YES.
Answer:
Therefore the population will be maximum when x=30 inches.
Step-by-step explanation:
Given that, the mosquito population is a function of rainfall and can be approximated by the formula
where x is the number of inches of rainfall.
Differentiating with respect to x
Again differentiating with respect to x
Now we set N'(x)=0
Since at x=30, N''(x)<0, So at x=30, N(x) has maximum value.
Therefore the population will be maximum when x=30 inches.
Answer:
61.0
Step-by-step explanation:
Formula for Circle
2πr
π = 3.14
r = Radius
