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3 years ago

Log 3 x=4 pls and thx

Mathematics

1 answer:

Fantom [35]3 years ago

8 0

Answer:

Step-by-step explanation:

Using the law of logarithms

• $log_{b}$ x = n ⇔ x = $b^{n}$

given

$log_{3}$ x = 4 ⇒ x = $3^{4}$ = 81 → D

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Apr 24,8:28:53 AM Find the 98th term of the arithmetic sequence -10,-8, -6, ...

Nata [24]

Answer: 184

Step-by-step explanation:

The nth term of am arithmetic sequence is calculated as:

Nth term= a+(n-1)d

where a = first term

d = common difference

a = -10

d = -8 -(-10) = -8+10 = 2

98th term= a+(n-1)d

= -10 + (98-1)(2)

= -10 + (97×2)

= -10 + 194

= 184

The 98th term of the arithmetic sequence is 184

6 0

3 years ago

A rectangular prism has a width of 51 ft and a volume of 144 ft3. Find the volume of a similar prism with a width of 17 ft. Roun

meriva

Answer:

$5.3\ ft^3$

Step-by-step explanation:

Similar shapes with scale factor $k$ have proportional volumes with coefficient $k^3$ i.e.

$\dfrac{V_{large}}{V_{small}}=k^3,$

where

$k=\dfrac{\text{width of large prism}}{\text{width of small prism}}.$

Since

$\text{width of large prism}=51\ ft,\\ \\\text{width of small prism}=17\ ft,$

then

$k=\dfrac{51}{17}=3.$

Hence,

$\dfrac{144}{V_{small}}=3^3\Rightarrow V_{small}=\dfrac{144}{27}=\dfrac{16}{3}=5\dfrac{1}{3}\approx 5.3\ ft^3.$

7 0

3 years ago

What is 6.4 × 10−8 mi/day in feet per hour? (1 mi = 5280 ft)

oee [108]

The correct answer is B 1.408 × 10^−5 ft/h

8 0

3 years ago

A. -4,0,2 B. -2,0,4 C. -5,0,17 D. -17,0,5

Lostsunrise [7]

Answer:

You have three

-4,0, and 2 or the answer choice A

Step-by-step explanation:

3 0

3 years ago

A 24-centimeter by 119-centimeter piece of cardboard is used to make an open-top box by removing a square from each corner of th

satela [25.4K]

Answer:

The size square removed from each corner = 32.15 cm²

Step-by-step explanation:

The volume of the box = Length * Breadth * Height

Let r be the size removed from each corner

Note that at maximum volume, $\frac{dV}{dr} = 0$

The original length of the cardboard is 119 cm, if you remove a size of r (This typically will be the height of the box) from the corner, since there are two corners corresponding to the length of the box, the length of the box will be:

Length, L = 119 - 2r

Similarly for the breadth, B = 24 - 2r

And the height as stated earlier, H = r

Volume, V = L*B*H

V = (119-2r)(24-2r)r

V = r(2856 - 238r - 48r + 4r²)

V = 4r³ - 286r² + 2856r

At maximum volume dV/dr = 0

dV/dr = 12r² - 572r + 2856

12r² - 572r + 2856 = 0

By solving the quadratic equation above for the value of r:

r = 5.67 or 42

r cannot be 42 because the size removed from the corner of the cardboard cannot be more than the width of the cardboard.

Note that the area of a square is r²

Therefore, the size square removed from each corner = 5.67² = 32.15 cm²

5 0

3 years ago