Answer:
4/10 and can be simplified to 2/5
Step-by-step explanation:
Answer:
10.5618feet, 0.8125sec
Step-by-step explanation:
Given the height reached by the catapult expressed by the equation H=-16T^2+26T
At the maximum height, the velocity of the object is zero, hence;
v = dh/dt = 0
-32t + 26 = 0
-32t = -26
t = 26/32
t = 0.8125secs
Hence it will attain the maximum height after 0.8125second
Substitute t = 0.8125s into the expression to get the maximum height
H=-16t^2+26t
H = -16(0.8125)^2 + 26(0.8125)
H = -16(0.6602) + 21.125
H = -10.5632+21.125
H = 10.5618
hence the maximum height reached by the ball is 10.5618feet
9514 1404 393
Answer:
5z^(-5/3)
Step-by-step explanation:
The rules of exponents being used here are ...
![\sqrt[n]{a}=a^{1/n}\\\\\dfrac{a^b}{a^c}=a^{b-c}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B1%2Fn%7D%5C%5C%5C%5C%5Cdfrac%7Ba%5Eb%7D%7Ba%5Ec%7D%3Da%5E%7Bb-c%7D)
Using these rules on the given expression, we find ...
![\dfrac{10\sqrt[3]{z}}{2z^2}=\dfrac{10}{2}z^{1/3-2}=\boxed{5z^{-5/3}}](https://tex.z-dn.net/?f=%5Cdfrac%7B10%5Csqrt%5B3%5D%7Bz%7D%7D%7B2z%5E2%7D%3D%5Cdfrac%7B10%7D%7B2%7Dz%5E%7B1%2F3-2%7D%3D%5Cboxed%7B5z%5E%7B-5%2F3%7D%7D)
The answer you are looking for is B
Answer:
-11, -1, 0, 6/5, 1.25
Step-by-step explanation:
