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andreyandreev [35.5K]
2 years ago
14

Can some one write a system for all of these? it would really help me rn :(

Mathematics
1 answer:
tatiyna2 years ago
8 0

Answer: 36 and 56

Step-by-step explanation: the sum of two numbers translates into x + y = 92

If the difference would be 0 then the numbers would be equal.

Just choose which number you want to be bigger. If x is bigger then x - y = 20. If y is bigger then y - x = 20.

Let’s make x bigger so x-y=20. You can go two ways with this.

Either x=20+y because when passing one term from one side to the other you can change the sign.

Or y=x-20 because you pass “-y” to the right and it’s becomes “y” and you pass 20 to the left and it becomes -20.

Let’s go with y=x-20.

Now we replace this in the other relation:

X + Y = 92

X + (x-20) = 92

X + X - 20 = 92

2x - 20 = 92 ==> 2x = 92 + 20 ==> 2x = 112 ==> 112/2 ==> x=56

Y = x - 20 ==> y = 56 - 20 ==> y = 36.

If you choose x=20+y and replace x in the other relation you’ll find out y first and only after that you’ll find x.

Hope this helps☺️

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If 1 ft = 1.894 x 10​ -4​miles, convert 20.0 inches to miles
Yakvenalex [24]

Answer:

3.1567 * 10^-4 miles

Step-by-step explanation:

1 ft = 1.894 * 10^-4 miles , so

1 inch = 1.894 * 10^-4 / 12  miles

= 0.15783 * 10^-4

= 1.5783* 10^-5 miles  ( in scientific form).

Multiplying this by 20 we get

31.567 * 10^-5

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2 years ago
An easier question all wrong or unhelpful or no-work answers will be reported.
ipn [44]
Elimination: 

3x - 9y = 3
6x - 3y = -24

3x - 9y = 3
18x - 9y = -72
(subtract)
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x = -5

(3 × -5) - 9y = 3
-15 - 9y = 3
+ 15
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Substitution:

6x - 3y = -24
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6x = -24 + 3y

÷ 6
x = 4 + 0.5y

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12 - 7.5y = 3
- 12
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x = 4 + (0.5 × 1.2)
x = 4 + 0.6
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So this one didn't fail as much, but I got different numbers. If you have to give in values, I'd give in the values from the elimination because I don't trust myself when it comes to the substitution
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A library receives 413 boxes of books and 125 boxes of magazines. There are 18 books in each box of books. How many total books
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Allushta [10]

Answer:

Step-by-step explanation:

9) PQR Is an isosceles triangle

=> ∠PRQ = (180° - x)/2

PRS is an isosceles right triangle

=> ∠PRS = 45°

Have: ∠PRS + ∠PRQ = 115°

=> \frac{180-x}{2}+45=115 \\

=> 180 - x = (115 - 45).2 = 140

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10) ABD is an isosceles right triangle => ∠ABD = 45°

BCD is an equilateral triangle => ∠CBD = 60°

have: x = ∠ABD + ∠CBD = 45° + 60° = 105°

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QTS   is an isosceles triangle => ∠TQS = 180 -2x

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have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)

(1)(2) => \left \{ {{y=x} \atop {2x-y=40}} \right.\\\\=> \left \{ {{x=40} \atop {y=40}} \right.

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∠JHF is the outer angle of the triangle FHG

=> 30° = 2x

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