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3 years ago

I need help :) ( 12 points)

Mathematics

1 answer:

Agata [3.3K]3 years ago

3 0

Answer:

Step-by-step explanation:

The graph starts at 15, so that's the y intercept and the Gallons of gasoline is going down so the slope is negative

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Please someone help me with this asap! Giving brainliest !!!!!!!!!

Lina20 [59]

Answer:

I thank its b not sure sorry if its wrong

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2 years ago

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Write one and two hundred fifty three thousandths in standard form

aivan3 [116]

1.253
Is the answer to ur question

6 0

3 years ago

CHECK MY WORK PLEASE

Likurg_2 [28]

Answer:

Letter D) $C(w)=75w+100$

Step-by-step explanation:

you have to pay $100 for the enrollment fee and w goes with 75 because you have to pay $75 per week.

Hope this helps

4 0

2 years ago

Hannah has a bag containing 2 Red, 4 purple, 4 Blue and 2 Green

juin [17]

Answer:

1/18

Step-by-step explanation:

there are 12 marbles in the bag

P(choose red) = 2/12 = 1/6

P(choose blue after replacement) = 4/12 = 1/3

P(choose red, then blue with replacement) = (1/6)(1/3) = 1/18

7 0

2 years ago

Find the average rate of change of the function over the given interval

sattari [20]

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\$

$\bf h(t)=cot(t)\implies h(t)=\cfrac{cos(t)}{sin(t)}\quad 
\begin{cases}
t_1=\frac{\pi }{4}\\
t_2=\frac{3\pi }{4}
\end{cases}\implies \cfrac{h\left( \frac{3\pi }{4} \right)-h\left( \frac{\pi }{4} \right)}{\frac{3\pi }{4}-\frac{\pi }{4}}
\\\\\\$

$\bf \cfrac{\frac{cos\left( \frac{3\pi }{4} \right)}{sin\left( \frac{3\pi }{4} \right)}-\frac{cos\left( \frac{\pi }{4} \right)}{sin\left( \frac{\pi }{4} \right)}}{\frac{\pi }{2}}\implies \cfrac{-1-1}{\frac{\pi }{2}}\implies \cfrac{-2}{\frac{\pi }{2}}\implies -\cfrac{4}{\pi }\\\\\\
-------------------------------\\\\$

$\bf h(t)=cot(t)\implies h(t)=\cfrac{cos(t)}{sin(t)}\quad 
\begin{cases}
t_1=\frac{\pi }{3}\\
t_2=\frac{3\pi }{2}
\end{cases}\implies \cfrac{h\left( \frac{3\pi }{2} \right)-h\left( \frac{\pi }{3} \right)}{\frac{3\pi }{2}-\frac{\pi }{3}}
\\\\\\$

$\bf \cfrac{\frac{cos\left( \frac{3\pi }{2} \right)}{sin\left( \frac{3\pi }{2} \right)}-\frac{cos\left( \frac{\pi }{3} \right)}{sin\left( \frac{\pi }{3} \right)}}{\frac{9\pi -2\pi }{6}}\implies \cfrac{\frac{0}{-1}-\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}}{\frac{7\pi }{6}}\implies\cfrac{-\frac{1}{\sqrt{3}}}{\frac{7\pi }{6}}\implies -\cfrac{\sqrt{3}}{3}\cdot \cfrac{6}{7\pi }
\\\\\\
-\cfrac{2\sqrt{3}}{7\pi }$

8 0

3 years ago