Answer:
The cost of dinner alone was $37.145
Step-by-step explanation:
15%=0.15----Convert your percentage into a decimal
43.70*0.15=6.555----Multiply the cost of dinner with the decimal
$43.70-$6.555=$37.145----Subtract the last number(6.555) from the total(43.70) to get the cost of dinner alone of $37.145 -This is making you subtract the percentage from the total!
I hope this helped!
Answer:
x=28
Step-by-step explanation:
6(x+2)=180 Step 1: Write equation
6x+12=180 step 2: Expand the equation
6x=168 Step 3: Do 180-12 first
x=28 Step 4: Divide by 6 answer you got in Step 3
Step 5: replace 28 with x to see if it's correct 6(28+2)= 180
Put comment if answer is wrong and i will change my answer soon as possible
I hope this helps
This is the easiest way to solve this problem:
Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __
For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
<u>10</u> <u> 9 </u> <u> 8 </u> __
4th can't be repeated so only 7 options left
<u>10</u> <u> 9 </u> <u> 8 </u> <u> 7
</u><u>
</u>Multiply the four numbers together: 10*9*8*7 = 5040 combinations
For the next two do the same process as the one above.
If digits can be repeated? You have ten options for every wheel so it would look like this: <u>10</u> <u>10</u> <u>10</u> <u>10
</u>
10*10*10*10 = 10,000 combinations
If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.
<u>10</u> <u> 9</u><u> </u> <u> 9 </u> <u> 9 </u>
10*9*9*9 = 7290 combinations
Answer:
E
Step-by-step explanation:
19) Amount of oil in = amount of oil in final product
.025(x) + .09(40-x) = .055(40) (x = 2.5% amt 40 - x = 9% amt)
x = 21.54 L of 2.5 % then 9% = 18.46 L
