Help me out please ......................

Your cell phone plan allows you 400 minutes per month so far this month you have used 265 minutes and you have 7 days left write

kati45 [8]

7x + 265 ≤ 400
Hope this helps!

5 0

3 years ago

Help please! I've never been good at percents

Igoryamba

Answer:

the answer is: 64.9 but I'm not sure

5 0

3 years ago

the temperature of the water in Emily's fish tank was 78 degrees F on Sunday the water temperature was changed by -3 on Monday a

SpyIntel [72]

To solve this problem, let us analyze this step by step. The temperature for each day is as follows:

Water temperature on Sunday = 78 degrees F

Water temperature on Monday = changed by -3 degrees F

Water temperature on Tuesday = changed by 3 degrees F

We can see that the total change of water temperature from Sunday to Tuesday is:

-3 + 3 = 0

Therefore there is zero overall change. There the integer which represents the temperature change is “0”.

Since the overall change in water temperature is zero, hence the temperature on Sunday and on Tuesday is similar.

Water temperature on Tuesday = 78 degrees F

8 0

3 years ago

Which of the following activities are examples of data gathering? Check all that apply. A. Surveying students about their favori

katrin [286]

A. Surveying the students about their favorite type of math problem.
and
C. Sampling water for contaminants

6 0

2 years ago

Read 2 more answers

A sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's p

Grace [21]

Answer:

Yes, we have sufficient evidence at the 0.02 level to support the company's claim.

Step-by-step explanation:

We are given that a sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature claimed that above 29% do not fail in the first 1000 hours of their use.

Let Null Hypothesis, $H_0$ : p $\leq$ 0.29 {means that less than or equal to 29% do not fail in the first 1000 hours of their use}

Alternate Hypothesis, $H_1$ : p > 0.29 {means that more than 29% do not fail in the first 1000 hours of their use}

The test statics that will be used here is One-sample proportions test;

T.S. = $\frac{\hat p -p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of chips that do not fail in the first 1000 hours of their use = 32%

n = sample of chips = 1500

So, <u>test statistics</u> = $\frac{0.32-0.29}{\sqrt{\frac{0.32(1-0.32)}{1500} } }$

= 2.491

<em>Now, at 0.02 level of significance the z table gives critical value of 2.054. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it fall in the rejection region.</em>

Therefore, we conclude that more than 29% do not fail in the first 1000 hours of their use which means we have sufficient evidence at the 0.02 level to support the company's claim.

7 0

3 years ago