Answer:
T = 40 (minutes?)
Step-by-step explanation:
Given the equation G = 50 + 20T, where G = the total amount of gas and T = the amount of Time, we know that there is already 50 gallons of gas in the tank and that the rate at which it is pumped is 20 gallons per minute (I am assuming, though it is not stated in the problem). Given that the tank holds 850 gallons, we can plug in the values into the equation and solve for the missing variable, T:
850 = 50 + 2T
Subtract 50 from both sides: 850 - 50 = 50 + 2T - 50 or 800 = 2T
Divide 2 from both sides: 800/2 = 2T/2
Solve for T: 40 = T
Answer:
3x² + 8x - 9
Step-by-step explanation:
8x² - 5x² +x+7x-10+1
=3x² + 8x - 9
take x =initial deposit amount. then make equation:
x+75.5+55.25-25.15-18.65 = 210.85
simplify:
x+86.95 = 210.85
x=210.85 - 86.95
x=123.90
so Initial deposit amount is $123.90
check: 210.85+18.65+25.15-55.25-75.5 = 123.9
123.9 = 123.9
Answer:
the answer is A.
just took the test e2020
Step-by-step explanation:
Answer:
See the answers bellow
Step-by-step explanation:
For 51:
Using the definition of funcion, given f(x) we know that different x MUST give us different images. If we have two different values of x that arrive to the same f(x) this is not a function. So, the pair (-4, 1) will lead to something that is not a funcion as this would imply that the image of -4 is 1, it is, f(-4)=1 but as we see in the table f(-4)=2. So, as the same x, -4, gives us tw different images, this is not a function.
For 52:
Here we select the three equations that include a y value that are 1, 3 and 4. The other values do not have a y value, so if we operate we will have the value of x equal to a number but not in relation to y.
For 53:
As he will spend $10 dollars on shipping, so he has $110 for buying bulbs. As every bulb costs $20 and he cannot buy parts of a bulb (this is saying you that the domain is in integers) he will, at maximum, buy 5 bulbs at a cost of $100, with $10 resting. He can not buy 6 bulbs and with this $10 is impossible to buy 0.5 bulbs. So, the domain is in integers from 1 <= n <= 5. Option 4.
For 54:
As the u values are integers from 8 to 12, having only 5 possible values, the domain of the function will also have only five integers values, With this we can eliminate options 1 and 2 as they are in real numbers. Option C is the set of values for u but not the domain of c(u). Finally, we have that 4 is correct, those are the values you have if you replace the integer values from 8 to 12 in c(u). Option 4.
