Answer:
The way I was taught to do it is to change value into a total fraction, then multiple the numerators together, multiply the denominators together, and finally reduce as far as possible.
7/9 x 5 2/5 = 7/9 x 27/5 = 189/45 = 4 9/45 = 4 1/5
1 3/4 x 4 1/6 = 7/4 x 25/6 = 175/24 = 7 7/24
Answer:
1 and 2/13
Step-by-step explanation:
15 can go into 13 once with 2 left over.
Answer:
The sum is Rs 1,250 and Rs 650
Step-by-step explanation:
Let the amounts be represented as $x and $y
The sum of both is 1900
Thus;
x + y = 1,900 •••••(i)
Mathematically, the interest on the amount borrowed is;
I = PRT/100
where p is the principal, representing the amount borrowed
R is the rate
T is the time
for the first amount of $x ; we have interest as;
I = (x * 5 * 4)/100 = 20x/100
for the second, we have
I = (y * 9 * 4)/100 = 36y/100
The sum of both is 580
Thus;
20x/100 + 36y/100 = 580
20x + 36y = 58000 •••••(ii)
From equation i;
x = 1,900 - y
Substitute this into equation ii
We have this as;
20(1900-y) + 36y = 58,000
38000 - 20y + 36y = 58,000
16y = 58000 - 38000
16y = 20,000
y = 20,000/16
y = 1250
From equation 1;
x + y = 1900
x = 1900-y
x = 1900-1250
y = 650
Answer:
Step-by-step explanation: AB = 6-2=4 BC = 3 ( 3- ) = 6 ∙
<h3>
Calulate AC find the formula ~ d = ≅![\sqrt{x} 2-x1) + (x2 - y2) = 3,2 AC = \sqrt[n]{x} (3+3)2 + ( 2 - 6 ) 2 = \sqrt[n]{x} 36 + 16 = \sqrt{} 52 P = 4 + 6 \sqrt{} 52 17.21 to dec. places\\](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%202-x1%29%20%2B%20%28x2%20-%20y2%29%20%3D%203%2C2%20AC%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D%20%283%2B3%292%20%2B%20%28%202%20-%206%20%29%202%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D%2036%20%2B%2016%20%3D%20%5Csqrt%7B%7D%2052%20P%20%3D%204%20%2B%206%20%5Csqrt%7B%7D%2052%20%20%2017.21%20to%20dec.%20places%5C%5C)
</h3>
