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Rainbow [258]
3 years ago
8

In a survey of students , every student studies at least one of the three subjects Maths English and Science . The number of stu

dents who study only one subject is twice the number of students who study only two students . If 20 students study all three and 80 students who study only two subjects, find the total number of students in the survey. ​
Mathematics
1 answer:
Mandarinka [93]3 years ago
5 0

Answer:

80x2=160         20x3=60  160+60=220

Step-by-step explanation:

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Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

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b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

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c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

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Answer:

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Step-by-step explanation:

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3 years ago
Find the mean of 12 ,10,12,14,8,15,8,9,6,5​
il63 [147K]

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Step-by-step explanation:

Add up the scores and dividing the total by the number of scores.

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2 years ago
Read 2 more answers
Elliot has a total of 26 books. He has 12 more fiction books than nonfiction books. Let x represent the number of fiction books
Llana [10]
X and y are books
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sub
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