solution: x+5= -x-5
x= -5
1. Subtract 5 from both sides
2. Simplify
3. Add x from both sides
4. Simplify
5. Divide both sides by two
Answer: D= csc theta
Step-by-step explanation:
4(2x1) ahdnwixkeobej <—- ignore that I just needed to type 20 characters
Answer:
2a: (c)
5o: (1, 3) and (1,1)
3a: (b)
1a: (d)
4o: (b)
Step-by-step explanation:
2a: the equation of a circle circumference needs to be transformable to the form 
where 
is the center and <em>r</em> is the radius. (a) and (d) can’t be it because they contain non-zero factors on <em>xy</em>. (b) isn’t an equation.
5o: just put the given (<em>x</em>, <em>y</em>) into the equations and see if it holds. (2, 3) isn’t on the circumference of (1) because 
, (3, 1) isn’t on it either because 
.
3a: calculate the value of the left-hand side term of the equation using (<em>x</em>, <em>y</em>) from the given point <em>M</em>. That’s the difference of square distance to the center to the square radius 
. Thus it’s 0 if the point is on the circumference, negative if inside and positive if outside. You get 
, positive, so it’s outside the circle.
1a: see definition from 2a. Here, 
.
4o: insert the y from the straight line equation (r) (which can be equivalently transformed to 
) into the circumference equation. If it yields no solution, that’s outside, it there’s exactly one solution, that’s a tangent and if there are two solutions, it’s a secant. 
There are two solutions, so it’s a secant.
Answer:
96
lower right
Step-by-step explanation:
Part 1
Givens
a1 = - 20
d = +4
n = 30
Equation
a30 = a1 + (n - 1)d
Solution
a30 = -20 + (30 - 1)*4
a30 = -20 + 29*4
a30 = - 20 + 116
a30 = 96
=====================
Part 2
Formula
Sum = (a1 + L)*n/2
n = 30
So only the two on the right can be considered
a1 = -20
L = 96
Sum = (-20 + 96)30/2 is the bottom right. D if you think of it that way.
