All categories

3 years ago

Please help me, i need help i have been stuck on my unit one exam for four days now

Mathematics

1 answer:

NeX [460]3 years ago

5 0

Answer:

$93.50

Step-by-step explanation:

8:00 to 12:15 = 4hrs 15min

13:00 to 17:15 = 4hrs 15min

4hr + 4hr + 15min + 15min = 8hrs 30min

8.5 × 11 = 93.5

You might be interested in

Well, so here is some free brainiest !!!!!!

Yanka [14]

Thank youu..........

4 0

3 years ago

Read 2 more answers

Use 3.14 = 7 to find the volume of the composite shape below.

Aliun [14]

Awnser: 16022 in3

Step-by-step explanation:

find the volume of the 2 cones find the volume if the semicircle then add the 2 volumes together.

5 0

3 years ago

What is the repulsive force between two pith balls that are 13.0 cm apart and have equal charges of −24.0 nC?

daser333 [38]

Answer:

The repulsive force is $3.067\times10^{-4}N$ .

Step-by-step explanation:

Consider the provided information.

The coulomb's law to calculate the repulsive force: $F=\frac{kQ_1Q_2}{r^2}$

Where the value of k is 9.00×10⁹ Nm²/C²

Substitute the respective values in the above formula.

$F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{[(13 cm)(\frac{1m}{100cm} )]^2}$

$F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{(0.13 m)^2}$

$F\approx0.0003067N$

$F=3.067\times10^{-4}N$

Hence, the repulsive force is $3.067\times10^{-4}N$ .

8 0

3 years ago

Please help me asap!

diamong [38]

V= x*(10-2x)(8-2x)

for greatest volume, differentiate v w.r.t x and equate to 0,

dv/dx= (10-2x)(8-2x) + x(-2)(8-2x)+ x(10-2x)(-2)=0

you get x from solving the quadratic equation. volume will be max at that x

5 0

3 years ago

A spool of ribbon hold 6.75 m a craft buys 21 spools what is the total cost of the ribbon sells for 2 dollars per meter

kherson [118]

The answer would be $70.875

3 0

3 years ago