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marshall27 [118]
3 years ago
10

Pls answer it urgent pls I couldn't find answers for this anywhere Pls give answer with formulas and steps 4/9 ÷ -5/7

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0

Answer:

-28/45

Step-by-step explanation:

Here, we want to find the result of a division

What we have to do here is to flip the fraction on the right hand side , then change the sign from division to multiplication

We have this as;

4/9 * -7/5

= -28/45

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What is the solution to the system of two equations shown?
Nadya [2.5K]

The solution of the given system of equation is x = -3 and y = 4 respectively.      

<h3>What is a system of linear equations?</h3>

A system of linear equations can be defined as a number of equations needed to solve the equations. For n number of variables n number of equations are required.

The given system of equations is as,

y = 4x + 16                   (1)

y = −2x − 2                  (2)

In order to solve them, substitute equation (2) into (1) as follows,

4x + 16 = −2x − 2

=> 4x + 2x = -2 - 16

=> 6x = -18

=> x  = -3

Then, y = -2 × -3 - 2 = 4

Hence, the solution of the given system of equation is x = -3 and y = 4.  

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6 0
1 year ago
What is the solution of the quadratic system of equations? <br> give brainliest and extra points!!
ololo11 [35]

Try this solution:

The correct answer is 'a' only, where x= -4;-1 and y= -6;-21

4 0
3 years ago
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Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator
SpyIntel [72]
\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}
\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)

When x=3, you're left with

147=49a_1\implies a_1=\dfrac{147}{49}=3

When x=\sqrt2 or x=-\sqrt2, you're left with

\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}

Adding the two equations together gives -10=2a_5, or a_5=-5. Subtracting them gives 2\sqrt2=2\sqrt2a_4, a_4=1.

Now, you have

5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)
5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)
2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that a_2x^4=2x^4 and a_3(-3)(-2)=6a_3=-6. These alone tell you that you must have a_2=2 and a_3=-1.

So the partial fraction decomposition is

\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}
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Which of the equations below could be the equation of this parabola?
prohojiy [21]

Answer:

the answer would be C.

Step-by-step explanation:

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3 years ago
7.46 rounded to the nearest tenth
atroni [7]

Answer:

7.5

Step-by-step explanation:

3 0
3 years ago
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