Given:
A plane is normal to the vector = -2i+5j+k
It contains the point (-10,7,5).
To find:
The component equation of the plane.
Solution:
The equation of plane is
Where, 
is the point on the plane and 
is normal vector.
Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is
Therefore, the equation of the plane is .
Answer:
x = -7
Step-by-step explanation:
First we find the slope using
m = ( y2-y1)/(x2-x1)
= ( -8 - 5)/( -7 - -7)
= (-8-5)/(-7+7)
= -13/0
This means the slope is undefined and the line is vertical
Vertical lines are in the form
x= constant and the constant is the x value of the points
x = -7
You need to add the number of blocks or lines are betweenhem.
-8/7
6- -2= 8
3- -4=7
rise over run the slope of K is 7/8
perpendicular is the negative inverse of the slope so it ends up as -8/7
Answer:24 miles/50$
Step-by-step explanation:
thats what i got
