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ale4655 [162]
4 years ago
14

Mike has attempted 84 free throws. Of those attempted, 63 have gone in the basket. Based on this rate, what is the probability t

hat Mike's next free throw attempt will go in the basket?
Mathematics
1 answer:
zhannawk [14.2K]4 years ago
5 0

Answer :P(\text{ Mike's next free throw attempt will go in the basket })= 0.75

Explanation:

Since we have given that ,

Total number of free throws Mike has =84

Number of free throws have gone in the basket = 63

As we know that

P(\text{ Mike's next free throw attempt will go in the basket})= \frac{\text{Number of favourable outcome}}{\text{Total number of outcomes}}

P(\text{ Mike's next free throw attempt will go in the basket })= \frac{63}{84}

∴  P(\text{ Mike's next free throw attempt will go in the basket })= 0.75


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