How can I remember what I learned in school?

1 answer:

7 0

For short term remembering: It really works if you take notes in class. I also found making connections to things you've experienced helps too.

For long term remembering - I found reviewing what you've learned recently is extremely useful. You can usually do this once in a couple of days until you're sure you can remember it.

Hope this helps!

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PLEASE HELP !! IT WOULD BE GREATLY APPREACIATED ! I DONT KNOW HOW TO DO THIS

serg [7]

(A) Bella's TV ratio of sides: 36"/27" = 1.333...

Lenny's: 52"/29.25" = 1.777...

Bella's and Lenny's TVs are NOT similar - their side ratios are different. Bella's is 4:3 while Lenny's is close to 16:9.

(B) Bella's TV has an exact ratio of 4:3 (36/27=4/3) and so is the older type.

Lenny's TV has a ratio of 52"/29.25". Divide both 52 and 29.25 by 3.25 to get 16/9, or 16:9. So Lenny's is the newer type.

4 0

3 years ago

What is the value of y in y-5=3-9(y+2)

Irina18 [472]

Y-5=3-9(y+2). so so u are going to distribute-9 to y and 2 which is -9y-18

so u are going to add like terms 3 and -18 which is -15. so the next step is going to be y-5=-9y-15 so u are going to add 5 to -5 and -15 to balance the equation and u will get -10 . y=-9y -10. since u are multiplying -9 by y so have to expand it y= -9 * y -10. so u have to divide y by y to get y . -9-10= -19 soo y =-19

3 0

3 years ago

Evaluate the function

Sedaia [141]

$f(0) = {4}^{3 \times 0 + 3} = {4}^{0 + 3} = {4}^{3} = 64$
The answer is above.
Additional note 1:
${4}^{3} = 4 \times 4 \times 4 = 16 \times 4 = 64$
Additional note 2:
In the answer I filled in "0" at the place where "n" was. This is because the question tells us n=0

4 0

3 years ago

How do i solve (4+6i)+(8-10i)?

ELEN [110]

Answer:

12- 4i

Step-by-step explanation:

(4+6i)+(8-10i)

4+6i+8-10i

4+8+6i-10i

12-4i

6 0

3 years ago

Find the value of x. Round your answer to the nearest tenth.

Fantom [35]

Hello again! So we will be using the pythagorean theorem ( $leg^2+leg^2=hypotenuse^2$ ) to solve for the bottom leg of the triangles. After we do that, we'll subtract the value of the legs from 31, and that'll be x.

Plug in 17 and z (or any variable that isn't x) into the leg variable and 19 into the hypotenuse variable, and from there we can solve.

$17^2+z^2=19^2$

Solve the exponents to get $289+z^2=361$

Subtract 289 on each side to get $z^2=72$

Lastly, square root each side of the equation and your answer should be $z= \sqrt{72}$ (To get more accurate answers, you shouldn't round until the end of the problem)

Nextly, we will need to subtract $\sqrt{72}$ from 31. And since there are 2 triangles, you'll need to multiply $\sqrt{72}$ by 2.

$x=31- \sqrt{72} *2 \\ x=14.0$

In short, x = 14.0

5 0

3 years ago