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3 years ago

Help me with math earn 10 points

Mathematics

2 answers:

gayaneshka [121]3 years ago

8 0

Answer:

Option number 1

Step-by-step explanation

shtirl [24]3 years ago

3 0

Answer: option 3

Step-by-step explanation:

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I NEED HELP ON THIS PROBLEM!!! PLEASE

Allushta [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$5x+8y=-9\implies 8y=-5x-9\implies y=\cfrac{-5x-9}{8} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{5}{8}} x-9\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

well then, so since this equation has that slope therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{-5}{8}} ~\hfill \stackrel{reciprocal}{\cfrac{8}{-5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{8}{-5}\implies \cfrac{8}{5}}}$

so we're really looking for the equation of a line whose slope is 8/5 and runs through (10,10)

$(\stackrel{x_1}{10}~,~\stackrel{y_1}{10}) ~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{8}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{\cfrac{8}{5}}(x-\stackrel{x_1}{10})$

5 0

2 years ago

Knowing that 6 × 7 = 42, we know that 42 ÷ 7 = ___

tatiyna

Answer:

Knowing that 6 × 7 = 42, we know that 42 ÷ 7 = 6

Step-by-step explanation:

Sorry but its very simple question you need to try to do it by yourself

3 0

3 years ago

Read 2 more answers

Gina will pay $14 for fabric at a crafting store. The tax rate is 8.5%. How much will she pay for her fabric including tax?

Gwar [14]

Answer:

$15.19

Step-by-step explanation:

8.5% = 0.085

0.085 x 14 = $1.19

1.19+14= $15.19

7 0

3 years ago

If the second term of a geometric sequence of real numbers is -2 and the fifth term is 16 then what is the fourteenth term?

Agata [3.3K]

<h3>Given</h3>

A geometric sequence such that ...

$a_2=-2\quad\text{and}\quad a_5=16$

$a_{14}$

<h3>Solution</h3>

We can use the ratio of the given terms to find the common ratio of the sequence, then use that to find the desired term from one of the given terms. We don't actually need the common ratio (-2). All we need is its cube (-8).

$a_2=a_1r^{(2-1)}=a_1r^1\\a_5=a_1r^{(5-1)}=a_1r^4\\a_{14}=a_1r^{(14-1)}=a_1r^13=a_5r^9\\\\\dfrac{a_5}{a_2}=\dfrac{a_1r^4}{a_1r^1}=r^3=\dfrac{16}{-2}=-8\\\\r^9=\left(r^3\right)^3=(-8)^3=-512\\a_{14}=a_5(-512)\\\\a_{14}=-8192$

7 0

3 years ago

Helppppppppppp !!!!!!!!!!!!!!!!!!!!!!

trapecia [35]

Answer: y = (1/2)x + 2

Explanation

4 0

3 years ago

Read 2 more answers