
As we know ~
Area of the circle is :

And radius (r) = diameter (d) ÷ 2
[ radius of the circle = half the measure of diameter ]
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
<h3>Problem 1</h3>



Now find the Area ~




・ .━━━━━━━†━━━━━━━━━.・
<h3>problem 2</h3>



Bow, calculate the Area ~




・ .━━━━━━━†━━━━━━━━━.・
<h3>Problem 3 </h3>




・ .━━━━━━━†━━━━━━━━━.・
<h3>Problem 4</h3>



now, let's calculate area ~



・ .━━━━━━━†━━━━━━━━━.・
<h3>problem 5</h3>



Now, let's calculate area ~




・ .━━━━━━━†━━━━━━━━━.・
<h3>problem 6</h3>




➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
Look online and find the answers to the workbook that's what I did and I never failed workbook things
The arcsine,

, is the inverse of the

function. This means that it takes as <em>inputs </em>what would usually be <em>outputs </em>for the

function and produces as <em>outputs </em>what would usually be <em>inputs </em>for the

function.
This can be particularly useful when you're trying to find an angle on a right triangle, but you've only been given the lengths of the sides. To find any angle

in a right triangle, just take

, where o is the side opposite

and h is the hypotenuse of the right triangle.
Answer:
24 will be your answer.
Step-by-step explanation:
A and D because the text states the moon rises from the east and sets in the west, but it can rise earlier in the day when the sun is brighter than the moon so you can't see the moon.