Ask question

Ask question

All categories

3 years ago

9

Sabendo que a soma de três termos consecutivos de uma progressão aritmética é 18 e que o seu produto é 16, determina esses númer

os.

1 answer:

Sholpan [36]3 years ago

6 0

Answer:

pog champers!

Step-by-step explanation:

You might be interested in

three adults and four children must pay $122 for tickets. Two adults and three children must pay $87. what are the price of each

Natasha2012 [34]

Let $a$ be the price of an adult ticket, and $c$ the price of a child ticket.

The sentence "Three adults and four children must pay $122 for tickets" translates to $3a+4c = 122$

The sentence "Two adults and three children must pay $87" translates to $2a+3c = 87$

Which leads to the linear system

$\begin{cases} 3a+4c = 122\\2a+3c = 87 \end{cases}$

You can solve this system as you prefer, for example you can multiply the first equation by 2 and the second by 3 to get

$\begin{cases} 6a+8c = 244\\6a+9c = 261\end{cases}$

Now subtract the first from the second:

$(6a+9c) - (6a+8c) = 261-244 \iff c = 17$

Now plug this value for c in any of the equations, for example the first:

$3a+4c = 122 \iff 3a+4\cdot 17 = 122 \iff 3a+ 68=122 \iff 3a = 54 \iff a = 18$

5 0

3 years ago

PLS HELP THIS IS A TEST

Pie

Answer:

D: 7

Step-by-step explanation:

1.75 (7) + 4.50

12.25 + 4.50

= 16.75

16.75 < 20

8 0

3 years ago

Five Tickets To A Basketball Game Cost $60. How Much Do 2 Tickets Cost?

horsena [70]

60/5 is 12. So they are $12 each.

So what is $12*2=$24

8 0

3 years ago

Read 2 more answers

Find the greatest common factor of 8,10, 26

DiKsa [7]

Wouldn't it be 2 since it goes into all them equally.

4 0

3 years ago

Read 2 more answers

You have 16 yellow beads, 20 red beads, and 24 orange beads to make identical bracelets. What is the greatest number of the brac

zzz [600]

Answer:

4 bracelets

Step-by-step explanation:

We have been given that you have 16 yellow beads 20 red beads and 24 orange beads to make identical bracelet. We are asked to find the greatest numbers of bracelets you can make using all the beads.

To solve our given problem, we need to find greatest common factor of 16, 20 and 24.

Factors of 16: 1, 2, 4, 8, 16.

Factors of 20: 1, 2, 4, 5, 10, 20.

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24.

We can see that greatest common factor of 16, 20 and 24 is 4, therefore, you can make 4 bracelets using all the beads.

6 0

3 years ago