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ELEN [110]
3 years ago
15

Brainliest to the first correct answer!

Mathematics
2 answers:
Goryan [66]3 years ago
7 0

Answer:

D.

Step-by-step explanation:

You know that 0.25 went to 2.00. That means that it's a 1.75 jump. In order to jump the other two prices up and keep the ratio the same, you must also jump them 1.75.

0.05 + 1.75 = 1.80

0.10 + 1.75 = 1.85

To double check the ration we can look back on the original. 0.05 to 0.10 is a scale of 0.05. 0.10 to 0.25 is a scale of 0.15

Then we look at our new one. 1.80 to 1.85 is a scale of 0.05. 1.85 to 2.00 is a scale of 0.15.

The ratios stayed the same, so this is the correct answer.

I hope this helped :)

Slav-nsk [51]3 years ago
5 0
D I just took a good guess and got it right
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2 years ago
Write a x (-a)x 13 x a x (-a) x 13 in power notation
miss Akunina [59]

Answer:

a\times (-a)\times 13\times a\times (-a)\times 13 can be written in power notation as a^{4}\times 13^{2}

Step-by-step explanation:

The given expression

a\times (-a)\times 13\times a\times (-a)\times 13

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:

Let

a\times (-a)\times 13\times a\times (-a)\times 13

= [13\times13][(a\times (-a)\times a\times (-a)]

As

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So,

=[13^{2}][a^2\times (-a)^2]

As

(-a)^2 = a^{2}

So,

=[13^{2}][a^2\times a^2]

As ∵a^{m} \times a^{n}=a^{m+n}

=[13^{2}][a^{2+2}]

As ∵a^{m} \times a^{n}=a^{m+n}

=13^{2}\times a^{4}

=a^{4}\times 13^{2}

Therefore, a\times (-a)\times 13\times a\times (-a)\times 13 can be written in power notation as a^{4}\times 13^{2}

<em>Keywords: power notation</em>

<em>Learn more about power notation from brainly.com/question/2147364</em>

<em>#learnwithBrainly</em>

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Step-by-step explanation:

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