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vitfil [10]
3 years ago
10

STOP SCROLLING HELP ME PLSSSSSS!

Mathematics
1 answer:
quester [9]3 years ago
5 0

Answer:

use proportions??

Step-by-step explanation:

i

d

k

h

o

w

t

o

do

this i am only in 5th grade yikes

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You must work 64 hours this month.
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X+56<533. What is the solution of the inequality?
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Find an ordered pair that is a solution to the equation.
AveGali [126]

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(x,y) = (4,1)

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If an experimenter sets equal to .01, then she is defining a "statistically rare" event as an event occurring more than one time
Fynjy0 [20]

Answer:

The correct answer is an event occurring one or fewer times in 100 times if the null hypothesis is true.

Step-by-step explanation:

For a statistically rare event, its probability is relatively small and the event is very unlikely to occur.  Therefore, if an experimental sets equal to 0.01 which is statistically rare, then we can interpret this mathematically as:

p(event) = 0.01 = 1/100

where p(event) is the probability of the event.

In addition, statistically, null hypothesis signifies no major difference between the specified parameters, and any obvious difference that might occur as a result of experimental error. Thus, it can be concluded that the event is occurring one or fewer times in 100 times if the null hypothesis is true.

3 0
3 years ago
Plssss help quick i need it for sum important
Vanyuwa [196]

(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

7 0
3 years ago
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