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Nata [24]
3 years ago
11

A hyperbola centered at the origin has a vertex at (3, 0) and a focus of the hyperbola is located at (9,0). What are

Mathematics
1 answer:
MariettaO [177]3 years ago
5 0

Answer:

Step-by-step explanation:

x²/a² - y²/b² = 1

center (0,0)

vertex (3,0), so a = 3

focus (9,0)

e = 9/a = 3

directrices: x = ±a/e = ±1

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valentinak56 [21]

Answer:

yes b

Step-by-step explanation:

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5 0
3 years ago
On a number line, point D is at -3, and point E is at 6. The point F lies on DE. The ratio of DF to FE is 2:3. Where does point
expeople1 [14]

Answer: point F is at <u>   0.6   </u> on the number line

=============================================================

Explanation:

The ratio 2:3 scales up to 2x:3x for some positive real number x.

This means the distance from D to F is 2x units, and the distance from F to E is 3x units. Combine those two smaller distances to get 2x+3x = 5x to represent the full distance from D to E.

D is at -3 and E is at 6. This is a distance of 9 units since |-3-6| = |-9| = 9

Set this equal to the 5x from earlier and solve

5x = 9

x = 9/5

x = 1.8

This leads to 2x = 2*1.8 = 3.6

Therefore, we'll move 3.6 units from -3 to -3+3.6 = 0.6 which is the location of point F on the number line.

Notice that from 0.6 to 6 is 5.4 units and that 3x = 3*1.8 = 5.4 matches up to help confirm the answer.

5 0
3 years ago
Solve E = mc2 for c. A) c = E m B) c = m E C) c = + m E D) c = + E m
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C=\sqrt{E/M}  

enjoy the rest of your day!

6 0
3 years ago
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1. 650 - 700 - 800 = ?<br>2. 25 - 45 + 23 =?​
butalik [34]
<h2>1. −850</h2><h2>2. 3</h2>

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6w-y=2z, Solve for the value of w
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6w-y=2z 6w=2z+y w=(2z+y):6 w=(z:3)+(y:6)
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3 years ago
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