Answer:
4, 6, 1
Step-by-step explanation:
We can solve this problem using a system of equations:
1) a + b + c = 11
2) 2a + 5b + 6c = 44
3) 4a - b = 10
First, we can substitute the value of b from equation #3 into equation #1:
b = 4a - 10
a + (4a - 10) + c = 11
5a - 10 + c = 11
5a + c = 21
c = 21 - 5a
Now, we can plug the values of b and c into equation #2, as b and c are represented in terms of a:
2a + 5(4a - 10) + 6(21 - 5a) = 44
2a + 20a - 50 + 126 - 30a = 44
-8a + 76 = 44
-8a = -32
a = 4
b = 4a - 10 = 4(4) - 10 = 6
c = 21 - 5a = 21 - 5(4) = 1
<span>1) distance formula; d = √(x2-x1)² +(y2-y1)² . d= √(-4-8)² +(-3-7)² = > d= 2√61
diameter = 2*radius => 2√61 =2r => r =√61 => r² =61
midpoint of the diameter is:
Xm= -4-8 /2 -6 => -6
Ym = -1-9 /2 -5 => -5 center of the cirlce is at (-6,-5)
</span><span>general equation of a circle: (x-x1)² +(y-y1)² =r² with (x1,y1) being the center of the circle.</span><span>
equation: (x+6)+(y+5)=61
</span>
Answer:
t=-6
Step-by-step explanation:
Step-by-step explanation:
c) j = 95 degree (similar triangle)
d) jk/4 = 4.6/9.2
jk/4 = 1/2
jk = ?
