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3 years ago

Which equations represent the line that is perpendicular to the line 5x – 2y = -6 and passes through the point

Mathematics

2 answers:

vitfil [10]3 years ago

6 0

Answer:

y+4=-(2/5)(x-5)

y=-(2/5)x-2

2x+5y=-10

Step-by-step explanation:

natta225 [31]3 years ago

4 0

Answer: 2x + 5y = - 10, Cy + 4 = (x-5)

Dy - 4 = (x+ 5)

Step-by-step explanation:

Equation of the line

5x - 2y = -6

Conditions for perpendicularity

m1 x m2 = -1

To get m1, rearrange the equation

2y = 5x + 6

y = 5x/2 + 3

n1 = 5/2 and m2 = -2/5

To get C

y = mx +c

-4 = -2 x 5/5 + C

-4 = -2 + C

C = -4 + 2

C = -2

To get the equation of the second line

y = -2x/5 - 2

Multiply through by 5

5y = -2x - 10

2x + 5y = 10.

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