Question

Solve the equation using square roots. 7x2 + 6 = 13

Answer 1

Answer:

The solution of the equation $7x^2+6=13$ is:

x=1 or -1

Step-by-step explanation:

$7x^2+6=13$

subtracting by 6 on both sides

$7x^2+6-6=13-6$

$7x^2=7$

dividing by 7 on both sides, we get

$x^2=1$

taking square roots on both sides, we get

x=±√1

⇒ x=1 or -1

Answer 2

Move all terms not containing xx to the right side of the equation.
Since 66 does not contain the variable to solve for, move it to the right side of the equation by subtracting 66 from both sides.7x2=−6+137x2=-6+13Add −6-6 and 1313 to get 77.7x2=77x2=7Divide each term by 77 and simplify.
Divide each term in 7x2=77x2=7 by 77.7x27=777x27=77Reduce the expression by cancelling the common factors.
x2=77x2=77Divide 77 by 77 to get 11.x2=1x2=1Take the squaresquare root of both sides of the equationequation to eliminate the exponent on the left side.x=±√1x=±1The complete solution is the result of both the positive and negative portions of the solution.
Any root of 11 is 11.x=±1x=±1The complete solution is the result of both the positive and negative portions of the solution.
x=1,−1