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tankabanditka [31]
3 years ago
7

A circular plate has circumference 32.7 inches. What is the area of this​ plate? Use 3.14 for pie.

Mathematics
1 answer:
sveta [45]3 years ago
6 0

Answer: 85.13

Step-by-step explanation:

We know:

Circumference = 2*3.14r

Area of a circle = 3.14r²

We need to find the radius given the circumference before solving for the area:

32.7 = 2*3.14r

32.7/6.28 = 6.28r/6.28

r = 5.20700637

Now that we know the radius, we can plug it in to find the area:

A = 3.14(5.20700637)²

A = 3.14(27.1129153)

A = 85.134554

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Isosceles trapezoid ABCD has legs If AB = 6y – 3, BC = 4y – 5, and CD = 7y – 18, find the value of y
castortr0y [4]

Answer:

The value of y is y=15

Step-by-step explanation:

We have:

AB = 6y – 3, BC = 4y – 5, and CD = 7y – 18

We define the isosceles trapezoid as it has two opposites parallel, the two other opposites legs are equal and also the diagonals are equal.

Here AB = CD

6y-3 = 7y-18

Combine the like terms:

18-3 = 7y-6y

15 = y

It means the value of y is  y=15....

4 0
3 years ago
The table above shows four numeric expressions. Which expression is an integer when it's evaluated?
Gre4nikov [31]

Answer: H

Step-by-step explanation:

9(-3)=-27, which is an integer.

8 0
2 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
NEED HELP FAST PLZ
san4es73 [151]

Answer:

you can use photomath or mathpapa

6 0
2 years ago
(-59)-(-18)/(+3)+(-2)(+4)+-27-(-3)
mojhsa [17]
-41/25 I believe, I'm not sure why you put some addition signs in the inside of parentheses
8 0
3 years ago
Read 2 more answers
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