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SVETLANKA909090 [29]
3 years ago
11

Need an answer quick!!

Mathematics
1 answer:
SOVA2 [1]3 years ago
4 0

Answer:

<h2><em><u><</u></em><em><u>6</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>55</u></em><em><u>°</u></em></h2>

Step-by-step explanation:

<em><u>Here</u></em><em><u>,</u></em>

<6 + 125° = 180° <em>[</em><em>Co-interior</em><em> </em><em>angles</em><em>]</em>

=> <6 = 180 - 125

=><em><u> <6 = 55° (Ans)</u></em>

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18n squared + 57n -10
aniked [119]
Most people use the decomposition method but i dont know how to do that so i use the Joes method a method similar to decomp. but easier.
canadian way

Find gcf: None
complet trinomial: 18n^2+57-10
find the product=10(18)
                       =-180
find the sum     =57
-3 and 60 goes into both meaning if you multiply 3 and60 you get -180 and if you add them you get 57.

so (n-3)(n+60)
divide by a in this case it 18
so (n<u>-3</u>)(n+<u>60</u>)
       18     18
do not divide. treat it like a fraction so you reduce it to lowest terms
(n<u>-3</u>)(n<u>-3)
</u>   18   10
<u /> at this point its reduced to lowest terms so now you take the deniminator and move it beside the "n"

=(18n-3)(10n-3)

therefore your answer is (18n-3)(10n-3)
I hoped this helped :)
3 0
4 years ago
A golfers score after playing on friday was +2
jek_recluse [69]

The end of his round on Saturday was a -5, and the end of his round on Sunday was a 0.

6 0
3 years ago
Ill give brainliest<br> Triangle Sum Theorem CLASSWORK
Viefleur [7K]

Answer:

8x + 32 + 116 = 180 \\ 8x + 148 = 180 \\ 8x = 180 - 148 \\ 8x =32  \\  \boxed{x = 4}

<h3>4 is the right answer.</h3>

(7x + 5) + 52 + 67 = 180 \\ 7x + 124 = 180 \\ 7x = 56 \\  \boxed{x = 8}

<h3>8 is the right answer.</h3>
3 0
3 years ago
Read 2 more answers
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
ANSWER FAST PLS HAVE 5 MIN FOR THIS
Kobotan [32]

Answer:

Y=375x

Step-by-step explanation:

thats the answer

6 0
4 years ago
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