Ratios of Area of the two squares = 25:9
So then let the areas be A1 = 25A and A2 = 9A, A is common element
Side of the smaller area S2 = 30 meters
Area of the smaller square A2 = 30 x 30 = 900
We have area of smaller square as 9A = 900 => A = 100
Area of the large square = 25A = 25 x 100 = 2500.
Hence S1^2 = 2500 => S1 = 50 meters which is 20 meters longer than the
side of the smaller square.
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➷ speed = distance / time
Rearrange this for time
time = distance/speed
time = 190/40
time = 4.75hrs
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Answer:
NT and MT
Step-by-step explanation:
Sorry I'm late lol.
The two segments form a right angle where they intersect, which is a common indication of perpendicular lines.
