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3 years ago

I’m confused on this one

Mathematics

1 answer:

Colt1911 [192]3 years ago

3 0

Call M the midpoint. The coordinate of this point is given by....

M=(x1+x2 /2, y1+y2 /2)

So (3,7)=(x1+0 /2, y1+ -5 /2). or

3= x1/2. or x1=6 and

7=y1-5 /2. or 14=y1-5 or y1=19

B is at the point (6,19)

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Evaluate expression -16 squared and write the result in form a + bi

coldgirl [10]

Writing it in the form of a+bi we get 0+4i

Step-by-step explanation:

We need to evaluate expression -16 squared and write the result in form a+bi

The given expression is: $\sqrt{-16}$

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Keywords: Complex Numbers

Learn more about Complex Numbers at:

#learnwithBrainly

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Eva8 [605]

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3 years ago

Read 2 more answers

Help would be nice, i’m out of school from covid

Mashcka [7]

SOLUTION:

We are to pick from the given tiles the pairs that are associated with each functions.

Note that each of the pairs are of the form (x,y) coordinates.

(1)

$y=6^x$

The correct tiles for this function with explanation are given as follow;

$\begin{gathered} (1,6)\text{ } \\ y\text{ = 6 when x =1 } \\ y=6^x \\ 6=6^1 \\ \text{Correct} \end{gathered}$ $\begin{gathered} (0,1) \\ y\text{ = 1 when x = 0} \\ y=6^x \\ 1=6^0 \\ \text{Correct} \end{gathered}$ $\begin{gathered} (2,36) \\ y=36\text{ when x = 2} \\ y=6^x \\ 36=6^2 \\ \text{Correct} \end{gathered}$ $\begin{gathered} (0.5,\sqrt[]{6)} \\ y\text{ = }\sqrt[]{6}\text{ when x = 0.5} \\ y=6^x \\ \sqrt[]{6}=6^{0.5} \\ \sqrt[]{6}=6^{\frac{1}{2}} \\ \sqrt[]{6}\text{ = }\sqrt[]{6} \\ \text{Correct} \end{gathered}$

For the first function, above tried tiles are the associated ones any other one different from those explained above are not associated with the fuction.

(2)

$y=\log _6x$

The correct tiles for this function are given as follow;

$(6,1),\text{ (1, 0), (36 ,2) and (}\sqrt[]{6\text{ }}\text{ , 0.5)}$

Let me explain or prove two out of the four tiles.

$\begin{gathered} (6,\text{ 1)} \\ y\text{ = 1 when x =6} \\ y=\log _6x \\ 1=\log _66 \\ \text{Correct} \end{gathered}$ $\begin{gathered} (\sqrt[]{6},\text{ 0.5)} \\ y\text{ = 0.5 when x = }\sqrt[]{6} \\ y=\log _6x \\ 0.5\text{ =}\log _6\sqrt[]{6} \\ \frac{1}{2}=\log _66^{\frac{1}{2}} \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\log _66 \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\text{ x 1} \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\text{ } \\ \\ \text{Correct} \end{gathered}$

You can also use the approach above to confirm the remaining two.

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1 year ago