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iris [78.8K]
3 years ago
9

For Problems 11-12, expand the expressions using the Distributive Property. Then simplify the expressions. 12. 9(3y-5) ​

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
6 0

Answer:

27y-45

Step-by-step explanation:

9(3y-5)=27y-45

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The 8 students in Mrs. Alexander's class were asked how many minutes it takes them to get to school in the morning. Here is what
IrinaK [193]

To find the mean just add all of them then divide the result by 8. To find the median put the numbers in order. So 3, 3, 4, 4, 13, 15, 15, 16 then find the middle number, if there is not middle number (which there isn’t) add the two middle numbers (4 and 13) to get 17 then divide 17 by 2 to get 8.5 which is the median

7 0
3 years ago
The cross section of a water bin is shaped like a trapezoid. The bases a a trapezoid are 20 feet and 6 feet long. It has a area
nekit [7.7K]

Answer:

the height of the cross section is 3 feet

Step-by-step explanation:

The computation of the height of the cross section is shown below:

Area = 1 ÷ 2 × (a + b) × h

39 = 1 ÷ 2 × (20 + 6) × h

39 =  1 ÷2 × 26 × h

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= 3 feet

hence, the height of the cross section is 3 feet

3 0
3 years ago
True Statements Plz help me
Ket [755]

Answer:

Bvcvbcc

Step-by-step explanation:

Bbvvbbbbb

7 0
2 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

6 0
3 years ago
Read 2 more answers
I really need help i don’t get this at ALL. :(
bonufazy [111]

Step-by-step explanation:

You have to go to Y axis first then to X. For example : (4,5) go up 4 and go to x axis and when u get to 5 you put a dot. The same thing if is (-4,-5) go down 4 and to the left 5 and mark a dot. When you mark the dot put (_,_).

Hope you understand. Let me know if you don't.

6 0
3 years ago
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