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Nostrana [21]
3 years ago
6

Join this ID:80543 its a g i m k i t

Mathematics
1 answer:
vivado [14]3 years ago
4 0

Answer:

IT DOESNT" work

Step-by-step explanation:

thanks for the points :p

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A store is having a sale on trail mix and jelly beans. For 7 pounds of trail mix and 9 pounds of jelly beans, the total cost is
Vlad [161]

Answer:

The cost for each pound of trail mix is $ 1.75 and each pound of jelly beans is $ 2.75.

Step-by-step explanation:

Let each pound of trail mix cost x dollars and each pound of jelly beans cost y dollars.

Given:

7 pounds of trail mix and 9 pounds of jelly beans cost $ 37.

So, 7x+9y=37--------------- 1

Also, 5 pounds of trail mix and 3 pounds of jelly beans cost $ 17.

So, 5x +3y=17--------------- 2

Multiplying equation 2 by -3, we get

(5x +3y=17)\times -3\\-15x-9y=-51-------- 3

Now, adding equations 1 and 3, we get

7x+9y-15x-9y=37-51\\7x-15x=-14\\-8x=-14\\x=\frac{-14}{-8}=\$1.75

Now, plug in x=1.75 in equation 1 and solve for y.

7(1.75)+9y=37\\12.25+9y=37\\9y=37-12.25\\9y=24.75\\y=\frac{24.75}{9}\\ y=\$2.75

Therefore, the cost for each pound of trail mix is $ 1.75 and each pound of jelly beans is $ 2.75.

7 0
3 years ago
How do you find the square root of a number?
joja [24]
By taking square root of a number using calculator
5 0
3 years ago
Mathematical induction, prove the following two statements are true
adelina 88 [10]
Prove:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+n\left(\frac12\right)^{n-1}=4-\dfrac{n+2}{2^{n-1}}
____________________________________________

Base Step: For n=1:
n\left(\frac12\right)^{n-1}=1\left(\frac12\right)^{0}=1
and
4-\dfrac{n+2}{2^{n-1}}=4-3=1
--------------------------------------------------------------------------

Induction Hypothesis: Assume true for n=k. Meaning:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}=4-\dfrac{k+2}{2^{k-1}}
assumed to be true.

--------------------------------------------------------------------------

Induction Step: For n=k+1:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}

by our Induction Hypothesis, we can replace every term in this summation (except the last term) with the right hand side of our assumption.
=4-\dfrac{k+2}{2^{k-1}}+(k+1)\left(\frac12\right)^{k}

From here, think about what you are trying to end up with.
For n=k+1, we WANT the formula to look like this:
1+2\left(\frac12\right)+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}=4-\dfrac{(k+1)+2}{2^{(k+1)-1}}

That thing on the right hand side is what we're trying to end up with. So we need to do some clever Algebra.

Combine the (k+1) and 1/2, put the 2 in the bottom,
=4-\dfrac{k+2}{2^{k-1}}+\dfrac{(k+1)}{2^{k}}

We want to end up with a 2^k as our final denominator, so our middle term is missing a power of 2. Let's multiply top and bottom by 2,
=4+\dfrac{-2(k+2)}{2^{k}}+\dfrac{(k+1)}{2^{k}}

Distribute the -2 and combine the fractions together,
=4+\dfrac{-2k-4+(k+1)}{2^{k}}

Combine like-terms,
=4+\dfrac{-k-3}{2^{k}}

pull the negative back out,
=4-\dfrac{k+3}{2^{k}}

And ta-da! We've done it!
We can break apart the +3 into +1 and +2,
and the +0 in the bottom can be written as -1 and +1,
=4-\dfrac{(k+1)+2}{2^{(k-1)+1}}
3 0
3 years ago
Which equation represents a population of 320 animals that decreases at an annual rate of 19%
kotegsom [21]
320 times .19t
t being the number of years
6 0
3 years ago
Identfy the equation that translates Y= In(x) five units down.
mariarad [96]

Answer:

y= In(x)-5

Step-by-step explanation:

3 0
3 years ago
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