57.10
70.9
these are only the answers for the first two problems
Answer:
1st one m=0
y= <u>0.49875311x / cm </u>
<u>No horizonal asymptotes</u>
<u>x= 1/2 + 2.005 mcy</u>
<u />
<u>2nd one is </u>
<u>slope 1/2</u>
<u>y intercept (0,2)</u>
<u />
<u>x y</u>
<u>-4 0</u>
<u>0 2</u>
<u />
Step-by-step explanation:
for 2
starting point ay y 2 make a point
then rise over run
go up 1 and to the right 2 and point , then up 1 and to the right 2 and point
there is your graph
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
The radius of the cylinder will be
<h3>What will be the radius of the cylinder?</h3>
It is given that


Now we know that

putting values in the formula



Thus the radius of the cylinder will be
To learn more about the Volume of the cylinder follow
brainly.com/question/9554871
Answer:
x = 16
Step-by-step explanation:
2(x - 1) - 6 = 24 ( add 6 to both sides )
2(x - 1) = 30 ( divide both sides by 2 )
x - 1 = 15 ( add 1 to both sides )
x = 16