All categories

3 years ago

Trigonometry question

Mathematics

1 answer:

kaheart [24]3 years ago

8 0

Answer:

Step-by-step explanation:

$\tan \theta=\frac{perpendicular}{base} \\\tan 45=\frac{2200}{d} \\1=\frac{2200}{d} \\d=2200~ft.$

You might be interested in

$3.00 for 150 golf tees

stepladder [879]

Answer:

2 cents a tee

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What’s the answer to (5 x 10^4) x (6 x 10^9) please help me

san4es73 [151]

Answer: 300000000000000 Scientific Notation: 3 x 10^14

Step-by-step explanation: (5 x 10^4) = 50000 (6 x 10^9) = 6000000000

50000 x 6000000000 = 300000000000000

7 0

2 years ago

Jake is saving for a new tablet. It costs $250, and he has $100. He earns $5 per week for doing chores. Jake wants to figure out

kirza4 [7]

Answer: 250 ≤ 100+5x

150≤5x divide by 5

30≤x

It will take 30 weeks to earn enough.

Step-by-step explanation:

7 0

2 years ago

Look at this list of numbers.

Vlad [161]

Answer:

3 5 -5 2 and 7 are the numbers

5 0

3 years ago

N1=731pˆ1=0. 33 n2=644pˆ2=0. 28 use this data to find the 90onfidence interval for the true difference between the population pr

postnew [5]

The 90% confidence interval for the true difference between the population proportions is [ - 0.0908, - 0.0092]

Given,

$N_{1}$ = 731

$N_{2}$ = 644

$P_{1}$ = 0.33

$P_{2}$ = 0.28

z score for 90% confidence interval = 1.645

Here, the confidence interval formula :

( $P_{1} -P_{2}$ ) ± z $\sqrt{\frac{P_{1}(1-P_{1}) }{N_{1} }+ \frac{P_{2}(1-P_{2}) }{N_{2} } }$

Substituting the values, we get

(0.33 - 0.28) ± 1.645 $\sqrt{\frac{0.33(1-0.33)}{731}+\frac{0.28(1-0.28)}{644} }$

= 0.05 ± 1.645 $\sqrt{0.0003024624+0.0003130435}$

= 0.05 ± 1.645 $\sqrt{0.0006155059}$

= 0.05 ± 1.645 × 0.0248093914

= 0. 05 ± 0.0408114489

Confidence interval:

- 0.05 - 0.0408114489 = - 0.0908114489 ≈ - 0.0908

- 0.05 + 0.0408114489 = - 0.0091885511 ≈ - 0.0092

The confidence interval for the true difference between the population proportions is [ - 0.0908, - 0.0092]

Learn more about confidence interval here:brainly.com/question/17421912

#SPJ4

7 0

2 years ago