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If 2x^2 + 6x = 36 what are the possible values of x? specifically 2 answers?
1 answer:
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The equation of a circle:
(h,k) - the coordinates of the centre
r - the radius
The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints
The centre of the circle is (2,5).
The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
The radius is 5.
(h,k) - the coordinates of the centre
r - the radius
The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints
The centre of the circle is (2,5).
The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
The radius is 5.
The table is an exponential function, and the equation that represents this function is
The table is given as:
x F(x)
4 15
5 31
7 127
8 255
Rewrite the table as:
x F(x)
4 16 - 1
5 32 - 1
7 128 - 1
8 256 - 1
Express as a base of 2
x F(x)
4 2⁴ - 1
5 2⁵- 1
7 2⁷ - 1
8 2⁸ - 1
Notice that the function is 1 subtracted from 2 raised to the power of the input.
This is represented as:
Hence, the equation of the table is
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