One possible outfit is available because 1 pair of pants and 1 shirt is one outfit
Answer:
A viable solution is the ordered pair (0,0)
Step-by-step explanation:
we know that
The number of books cannot be a negative number
The number of books is a positive integer
The weight cannot be a negative number
therefore
A viable solution is the ordered pair (0,0)
Answer:
A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.
B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.
C. The expected value of X is 6.75, and the standard deviation of X is 2.17.
Step-by-step explanation:
The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.
With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

A. P(x=6)

B. P(x≥10)




C. The expected value (mean) and standard deviation of this binomial distribution can be calculated as:

Answer:
K of Kelvin
Step-by-step explanation: