Question

From a point 55 feet away from the foot of a tower, the angle of elevation of the top of the

Answer 1

Answer:

The height of the tower is approximately 95.263 feet

Step-by-step explanation:

The given parameters are;

The distance from the foot of the tower where the angle of elevation is measured = 55 feet

The angle of elevation to the top of the tower from a point 55 feet from the foot of the tower, θ = 60°

Therefore, by trigonometric ratio, we have;

$tan(\theta )= \dfrac{Opposite \ leg \ length}{Adjacent \ leg \ length} = \dfrac{The \ height \ of \ the \ tower}{Distance \ from \ foot \ of \ tower}$

Therefore, we have;

$tan(60 ^{\circ} ) = \dfrac{The \ height \ of \ the \ tower}{55 \ feet}$

The height of the tower = 55 feet × tan (60°) = 55 × √3 feet ≈ 95.263 feet.