Answer:
Step-by-step explanation:
Correct option is
D
[1,(1+π)
2
]
f(x)=(1+sec
−1
(x))(1+cos
−1
(x))
Here the limiting component is cos
−1
(x), since the domain of cos
−1
(x) is [−1,1].
Therefore,
f(1)=(1+0)(1+0)
=1
f(−1)=(1+π)(1+π)
=(1+π)
2
Hence range of f(x)=[1,(1+π)
2
]
Reversing the clauses of an "if-then" statement only sometimes makes the new statement true, so it isn't true or false. For example, reversing the clauses of "if 1=x, then x=1" makes the new statement true, but reversing the clauses of "if x=2, then |x|=2" doesn't.
Answer:
i think it's undefined
Step-by-step explanation:
The numerator is the top number of a fraction and the denominator is the bottom number of a fraction
Answer:
Step-by-step explanation:
<u>Let's derive a formula</u> :
⇒ Area (triangle) × 3 = Area (square)
⇒ 1/2(bh) × 3 = a²
∴ But a = h (shown in diagram)
⇒ 3/2(bh) = h²
⇒ <u>h = 3b/2</u>
<u>Now, taking tan θ</u> :
⇒ tan θ = b/h
⇒ tan θ = b/(3b/2)
⇒ tan θ = 2b/3b
⇒ tan θ = 2/3
