Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).
1 answer:
Answer:

Step-by-step explanation:
we know that
The area of a circle is equal to

In this problem we have

Substitute and find the area

Remember that
subtends the area of complete circle
so
by proportion
Find the area of the shaded regions
The central angle of the shaded regions is equal to 

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
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