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2 years ago

Find the missing segment

Mathematics

1 answer:

Alex73 [517]2 years ago

7 0

?=4
Step by step explanation: 14/x=7/2 which gets you 7x/28, you divide both sides by 7 to get that x=4

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HELP Find the value of x

emmasim [6.3K]

X=100
360-63= 297
297-80=217
217-100=117
117/3=39

4 0

2 years ago

What is the answer too 2(4w-1)=-10(w-3)+4

Advocard [28]

Answer:

w = 2

Step-by-step explanation:

2(4w - 1) = -10(w - 3) + 4

8w - 2 = -10w + 30 + 4

8w - 2 = -10w + 34

+10w +10w

18w - 2 = 34

+2 +2

18w = 36

18 18

w = 2

5 0

2 years ago

Simplify (4.2^n+1 _ 2^n+2 )/(2^n+1 _ 2^n).

irina [24]

4.2^n+12^n+2/2^n+12^n

Step-by-step explanation:

6 0

2 years ago

8x= 3x + 22 What's the solution?

Vinvika [58]

Step 1: Subtract 3x from both sides.8x−3x=3x+22−3x5x=22Step 2: Divide both sides by 5.5x5=225x=225Answer:x=225

8 0

2 years ago

Read 2 more answers

Currently, the demand equation for necklaces is Q = 30 – 4P. The current price is $10 per necklace. Is this the best price to ch

barxatty [35]

Answer:

The correct answer is NO. The best price to be charged is $3.75

Step-by-step explanation:

Demand equation is given by Q = 30 - 4P, where Q is the quantity of necklaces demanded and P is the price of the necklace.

⇒ 4P = 30 - Q

⇒ P = $\frac{30-Q}{4}$

The current price of the necklace $10.

Revenue function is given by R = P × Q = $\frac{1}{4}$ × ( 30Q - $Q^{2}$ )

To maximize the revenue function we differentiate the function with respect to Q and equate it to zero.

$\frac{dR}{dQ}$ = $\frac{1}{4}$ × ( 30 - 2Q) = 0

⇒ Q = 15.

The second order derivative is negative showing that the value of Q is maximum.

Therefore P at Q = 15 is $3.75.

Thus to maximize revenue the price should be $3.75.

6 0

2 years ago