Question

Andy is building a model of a square pyramid for a class project. The side length of the square base is 11 inches and the slant height of the pyramid is 15 inches. What is the surface area of the model pyramid?​

Answer 1

Answer:

The surface area of the model pyramid is $451\ in^{2}$

Step-by-step explanation:

we know that

The surface area of the pyramid is equal to

$SA=B+LA$

where

B is the area of the base of the pyramid

LA is the lateral surface of the pyramid

Find the area of the base B

$B=11^{2}=121\ in^{2}$ -----> is a square

Find the lateral surface area of the pyramid LA

we know that

The lateral surface area is equal to the area of its four triangular faces

$LA=4[\frac{1}{2}(11)(15)]=330\ in^{2}$

Find the surface area of the pyramid

Substitute the values

$SA=121+330=451\ in^{2}$