always true
Step-by-step explanation:
Assuming that you mean by true that it has solutions
we have
to know if it has real solutions we need to know if
is greater, equal or less than zero
if it's greater it's always
if it's equal it's sometimes
if it's less it's never
so
b=-9
a=3
c=-2
so it's always
Answer:
x = (-36)/5
Step-by-step explanation:
Solve for x:
(-10 x - 6)/2 = 33
Multiply both sides of (-10 x - 6)/2 = 33 by 2:
(2 (-10 x - 6))/2 = 2×33
(2 (-10 x - 6))/2 = 2/2×(-10 x - 6) = -10 x - 6:
-10 x - 6 = 2×33
2×33 = 66:
-10 x - 6 = 66
Add 6 to both sides:
(6 - 6) - 10 x = 6 + 66
6 - 6 = 0:
-10 x = 66 + 6
66 + 6 = 72:
-10 x = 72
Divide both sides of -10 x = 72 by -10:
(-10 x)/(-10) = 72/(-10)
(-10)/(-10) = 1:
x = 72/(-10)
The gcd of 72 and -10 is 2, so 72/(-10) = (2×36)/(2 (-5)) = 2/2×36/(-5) = 36/(-5):
x = 36/(-5)
Multiply numerator and denominator of 36/(-5) by -1:
Answer: (-36)/5
Answer:
y = 4
Step-by-step explanation:
We have to use the distributive property. Remember that the distributive property states that when expanding out a parentheses, you must find the sum of the product of the "outside term" with each of the "inside terms".
In this case, the "outside term" is 3 and the "inside terms" are y and 4. So, we need to multiply 3 by each of y and 4 and then add those together:
3(y + 4) = 24
3 * y + 3 * 4 = 24
3y + 12 = 24
Now, we subtract 12 from both sides to isolate the variable:
3y + 12 - 12 = 24 - 12
3y = 12
Finally, divide by 3 from both sides to get y alone:
3y/3 = 12/3
y = 4
Thus, y = 4.
Hope this helps!
Answer:
30 9/10
Step-by-step explanation: